Найти производные первого порядка данных функций

Y'=-8x2+x-4x5x2-7'=uv'=u'∙v-u∙v'v2, C'=0, xn'=n∙xn-1,u'=12∙u∙u', Cu'=C∙u',u±v'=u'±v', x'=1. =
=-8x2+x-4x5'∙x2-7--8x2+x-4x5∙x2-7'x2-72=
=-8∙x2'+x'-4∙x5'∙x2-7--8x2+x-4x5∙12∙x2-7x2-7'x2-7=
=-8∙2x+1-4∙5∙x4∙x2-7--8x2+x-4x5∙x2'-7'2∙x2-7x2-7=
=-16x+1-20x4∙x2-7--8x2+x-4x5∙2x2∙x2-7x2-7=
=-16x+1-20x4∙x2-7--8x2+x-4x5∙xx2-7x2-7=
=-16x+1-20x4∙x2-7--8x2+x-4x5∙xx2-7∙x2-7=
=-16x3+112x+x2-7-20x6+140x4+8x3-x2+4x6x2-7∙x2-7=
=-16x6+140x4-8x3+112x -7x2-7∙x2-7 .
Ответ: y'=-16x6+140x4-8x3+112x -7x2-7∙x2-7 .