Найти объем шара диаметром d=2 36 взяв π=3.14

V=4πr33=4πd233=πd36.
d=2.36⇒Δd=0.005,
δd=Δdd=0.0052.36=0.0021186=0.21186%;
π=3.14⇒Δπ=0.005,
δπ=Δππ=0.0053.14=0.0015924=0.15924%.
δV=δπd36=δπd3+δ6=δπ+δd3+δ6=
=δπ+3δd+δ6=0.005+3∙0.0021186+0=
=0.011356=1.1356%;
V=3.14∙2.3636=6.8788.
ΔV=VδV=6.8788∙0.011356=0.078116<0.5
V=6.9±0.08.
ΔV=∂V∂πΔπ+∂V∂dΔd=d36Δπ+πd22Δd=
=2.3636∙0.005+3.14∙2.3622∙0.005=0.054675,
δV=ΔVV=0.0546756.8788=0.0079483=0,79483%
V=6.89±0.055.