Найти производные функций y=lnx-12x+2+33x2

Y=lnx-12x+2+33x2 .
y/=lnx-12x+2+33x2/=u±v'=u'±v'; lnu'=1u∙u';uv'=u'∙v-u∙v'v2;xn'=n∙xn-1; x'=1 Cu'=C∙u'; C'=0.=
=lnx-12x+2/+3∙x23/=1x-12x+2∙x-12x+2/+3∙23∙x23 - 1=
=1x-12x+2∙x-12/∙x+2-x-12∙x+2/x+22+2∙x- 13=
=x+2x-12∙2∙x-1x-1/∙x+2-x-12∙1x+22+2∙x- 13=
=1x-12∙2∙x-1∙1∙x+2-x-12∙1x+2+23x=
=1x-12∙x-1∙2∙x+2-x-1x+2+23x=
=1x-1∙2x+4-x+1x+2+23x=x+5x-1x+2+23x
Ответ: y/=x+5x-1x+2+23x